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(3^x-7)=(2^x-7)
We move all terms to the left:
(3^x-7)-((2^x-7))=0
We get rid of parentheses
3^x-((2^x-7))-7=0
We calculate terms in parentheses: -((2^x-7)), so:We get rid of parentheses
(2^x-7)
We get rid of parentheses
2^x-7
Back to the equation:
-(2^x-7)
3^x-2^x+7-7=0
We add all the numbers together, and all the variables
3^x-2^x=0
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